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ENG·33 Engineering & Technology 6 MIN · 8 STATIONS

Stress concentration

A Socratic walk-through of stress concentration — reasoned out one step at a time, not lectured.

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a

The question we started with

THE QUESTION #

Why does a scratch far too small to weigh anything cut a steel plate's strength so sharply?

Take a steel plate ten millimetres thick and draw a scalpel across it, leaving a scratch a tenth of a millimetre deep. You have removed perhaps a thousandth of the cross-section, too little to weigh. Yet under a fluctuating load that plate may now crack at the scratch, at a stress the unscratched plate carries indefinitely.

The natural first thought is that strength must be proportional to the material left — which predicts a penalty of one part in a thousand. So either that thought is wrong, or something other than the missing metal is doing the damage.

b

Reasoning it through

REASONING #

Think about how load crosses a section. Every bit of force applied at one end must arrive at the other, travelling through whatever material is available. Picture the lines of force as traffic in lanes: put an obstruction in the middle and the traffic does not vanish, it crowds into the lanes beside it. The question is not how much road was lost but how tightly the traffic is squeezed going past — which already tells us the answer depends on the obstruction's shape, not its area.

Inglis worked this out in 1913 for an elliptical hole in a large plate under tension. Let a be the half-length of the ellipse measured across the load, and rho the radius at its tip. The stress at that tip comes out as the remote stress multiplied by

Kt = 1 + 2 times the square root of (a divided by rho).

Read that carefully, because it settles the question. The ratio inside the root is a shape ratio: how deep the flaw is compared with how sharply it ends. Nothing about the plate's width or the removed area appears at all.

Test it on a case we can check. A circular hole is an ellipse with equal axes, so its tip radius equals its half-width and the ratio is one: Kt is 3. A round hole triples the stress at its edge no matter how small it is — a pinhole is as bad as a coin-sized hole, which lost area cannot begin to explain.

Now the scratch. Suppose it is one millimetre deep and, being cut by something sharp, ends in a tip radius of a micrometre. The ratio is a thousand, its square root about thirty-two, so Kt is about sixty-five. The stress at the bottom of that scratch is sixty-five times the stress around it. That is the answer, and it comes out of the geometry alone.

Let us falsify the rival account rather than merely dismissing it. If lost cross-section were the mechanism, making a flaw bigger would always make things worse. But the standard repair for a crack in a plate is to drill a round hole at the crack tip: that removes more material and makes the part stronger, because it replaces a near-zero tip radius with the drill's and drops Kt from enormous to about three. No area-based account can produce that result.

c

The analogy

THE ANALOGY #
THE FIGURE

Think of tearing a sheet of paper. Pull an uncut sheet and it resists surprisingly well. Nick the edge with scissors and it opens along the nick with almost no effort. You did not remove enough paper to matter, and you can prove it: cut a broad semicircular bite out of the edge instead, removing far more paper, and the sheet is much harder to tear than the one with the tiny nick.

WHERE IT BREAKS DOWN

paper tears once and is done, whereas the scratched plate usually survives its first loading entirely and fails after thousands of cycles, so the notch's real work is to start something rather than to finish it.

d

Clarifying the model

THE MODEL #

Three refinements, where the honest engineering lives.

First, Kt is an elastic number, and steel is not merely elastic. Load the plate statically and the metal at the notch tip yields, blunting it and shedding load to its neighbours. That is why a ductile plate with a hole in it barely loses static strength: what governs is yielding across the remaining section, not the peak. The notch bites under fatigue, in brittle materials, at low temperatures, and wherever the metal cannot flow.

Second, the notch's severity in fatigue is not the full Kt. The measured strength reduction, conventionally Kf, is smaller by an amount depending on material and notch size, because the peak stress occupies a tiny volume and a crack must grow out of it into material far less stressed. Design practice therefore uses tested notch-sensitivity data rather than the geometric factor.

Third, the reconciliation with the sibling explanations here. Push the tip radius toward zero — a real crack rather than a machined notch — and Inglis gives infinite stress. That is not a discovery but a breakdown: elastic stress at a crack tip is not a usable quantity. Griffith's response was to abandon peak stress for an energy balance, the account behind the fibre-strength explanation in this collection, which yields strength falling as the inverse square root of flaw depth. The division of labour is clean: Kt describes flaws with a measurable tip radius, and the energy criterion takes over once the tip is atomically sharp. Tempered glass sidesteps both, holding its flaws shut under residual compression — it does not reduce Kt, it reduces the stress Kt multiplies.

Now the numbers, softest first. The value 3 for a circular hole is exact given Inglis's assumptions: a truly infinite plate under uniform remote tension. In a plate of finite width it differs with the ratio of hole to width, which is why handbooks print curves rather than a constant — I will not quote a figure. The value 65 is arithmetic on dimensions I chose for illustration, not a measurement of any real scratch. Which exposes the weakest link: the tip radius of an actual scratch is not measurable on a real component, so Kt for a genuine surface defect is not computable. It tells you which direction to move in, not a number for a stress report.

The load-bearing claim is the shape ratio itself: the multiplier is set by the flaw's depth relative to its tip radius, not by the material it removes — which is why polishing, radiusing a corner and stop-drilling a crack all work.

e

A picture of it

THE PICTURE #
Stress concentration
Stress concentration The horizontal axis is the shape ratio -- flaw depth compared with tip radius -- so each step right is a tenfold sharpening at constant depth, or a tenfold deepening at constant radius. The vertical axis is how many times the surrounding stress appears at the tip. Start at the far left, where the ratio is one: that is a circular hole, and the value 3 is the exact classical result. Then trace right to see why a scratch is not a small hole. The curve is plotted from the formula, not from measurements. {"generator":"[email protected]","source":"../Socrates/.diagram-cache/_src/stress-concentration.md","sourceIndex":1,"sourceLine":4,"sourceHash":"66d8dad77fa06148946f7f75c2b6bdd6ae07977bffce1f3b4a13869a97f93c51","diagramType":"xychart","layoutVariant":"source","repairedDuplicateIds":[],"motion":"entrance-with-reduced-motion-fallback","presentation":"editorial","attempt":1,"viewBox":{"x":0,"y":0,"width":798,"height":668},"qa":{"passed":true,"findings":[]}} 1 10 100 1000 10000 Flaw depth divided by tip radius 220 200 180 160 140 120 100 80 60 40 20 0 Peak stress divided by remote stress

How to readThe horizontal axis is the shape ratio — flaw depth compared with tip radius — so each step right is a tenfold sharpening at constant depth, or a tenfold deepening at constant radius. The vertical axis is how many times the surrounding stress appears at the tip. Start at the far left, where the ratio is one: that is a circular hole, and the value 3 is the exact classical result. Then trace right to see why a scratch is not a small hole. The curve is plotted from the formula, not from measurements.

f

What became clearer

WHAT CLEARED #
WHAT CLEARED

Strength is not shared out in proportion to material. Load has to get past an obstruction, and how hard it is squeezed doing so depends on how abruptly that obstruction ends. A scratch is dangerous because it is sharp, so an invisible defect can multiply local stress by tens. Which is why the useful question about a flaw is never how much metal it took, but what radius it left behind.

g

Where to go next

ONWARD #
  • Why stress gradient explains a small notch being less damaging than its Kt suggests.
  • How the stress intensity factor replaces Kt once the tip radius goes to zero.
h

Key terms

TERMS #
TermWhat it means
Stress concentration factor (Kt)the ratio of peak local stress at a geometric feature to the nominal stress away from it, fixed by shape alone.
Inglis solutionthe 1913 elastic result for an elliptical hole, giving Kt as one plus twice the root of depth over tip radius.
Notch sensitivitythe extent to which a material's fatigue strength actually falls by the full geometric factor.
Stop-drillingarresting a crack by drilling a round hole at its tip, replacing a sharp radius with a blunt one.

Every term the collection defines is gathered in the glossary.

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